常识在阅读考试中的运用

剖析以为,雅思阅读考试的文章以民众题材为主,内容涉及经济、教导、科技、医学、环境、能源、地质、海洋、动物等方面问题,而不涉及专业性很强的文章,以免给不同专业的考生造成优势或劣势;甚至有些知识都是我们日常生涯中所懂得的,因此在雅思浏览测验中,考生在拿到标题时可以首先考虑利用常识能否直接找出答案,而不是匆仓找定位词到文章中定位。下面我们结合题目具体说明常识在做题中的作用。

例一(剑六P71 The Search for the Anti-aging Pill)

Questions 33-37

Classify the following descriptions as relating to

A. caloric-restricted monkeys

B. control monkeys

C. neither caloric-restricted monkeys nor control monkeys

33. Monkeys were less likely to become diabetic.

34. Monkeys experienced more chronic disease.

35. Monkeys have been shown to experience a longer than average life span.

36. Monkeys enjoyed a reduced chance of heart disease.

37. Monkeys produced greater quantities of insulin.

解题:

首先读选项,我们会发现A 选项是卡路里即热量摄入受限制的猴子,而B选项,我们可以猜出它为热量摄入不受限制的猴子,当然若考生不判断可以到文章中定位找control monkeys,原文为“control animals that eat normally”,因此可以判断B选项为正常饮食即热量摄入不受限制的猴子。

接下来读题目,33题为“猴子成为糖尿病患者的几率减少”,依据常识我们都知道现在健康专家倡导人们减少卡路里即热量的摄入,因此我们可以判断此题答案为A; 而34题为“猴子阅历更多的慢性疾病”,依据同样的常识我又可以判断此题答案为B;36题为“猴子得心脏病的几率减少”,我们也可以得出答案为A。

35题和37题可能依据常识无法断定答案,这种情形下考生就须要应用定位词到文章中定位找答案了。

例二(剑五P89 Flawed Beauty: the problem with toughened glass)

Questions 18-23

Complete the summary with the list of words A-P below.

Toughened glass

Toughened glass is favored by architects because it is much stronger than ordinary glass, and the fragments are not as 18________ when it breaks. However, it has one disadvantage: it can shatter 19________. This fault is a result of the manufacturing process. Ordinary glass is first heated, then cooled very 20________. The outer layer 21________ before the inner layer, and the tension between the two layers……These are unstable, and can expand suddenly, particularly if the weather is 22________. If this happens, the pane of glass may break. The frequency with which such problems occur is 23________ by glass experts…….

解题:依据标题中的第一句话我们能猜出toughened glass为钢化玻璃,18题中讲当钢化玻璃破碎时,它的碎片不像普通玻璃一样____?依据常识我们知道钢化玻璃破碎时碎片不那么锐利,所以此题答案为F;同样依据常识,钢化玻璃有时会突然破碎,19题答案为I;20题考生若不断定答案可以应用定位信息到文章中定位答案,答案为C;21题我们又可以应用常识“热胀冷缩”,断定判断外层比内层先压缩,所以答案为K;22题同样应用“热胀冷缩”的常识,判断是天温暖的时候才会膨胀,因此断定答案为E;23题依据常识无法断定答案,考生应用定位信息到文章中定位断定答案,答案为L。


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